# Microelectronic Circuits Errata

## Microelectronic Circuits, 8th Edition Errata

Feel free to report additional suspected errors in the comments below. Note, some may already be corrected in your version of the text, particularly if you have the eBook.

### Appendix L – Answers to Selected Problems & Dropdown Answers in the eBook

These errors also appear in some eBook in the “hidden” (dropdown) answers.

### Appendix G – Comparison of the MOSFET and BJT

• Table G.3, page G-5, section on “Transconductance”: should be “gm = ” instead of “gm u“.
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Getu
5 months ago

In example 14.2 solution, the equal sign is placed after the gain and the gain comes before the equal sign. As a result, the formula appeared Vo/Vi – R2/R1 = 1/(1 + sC2R2) instead of Vo/Vi = (-R2/R1)(1/(1 + sC2R2).

Ron Bonne
1 year ago

Answer to problem 1.7 in Appendix L on the website shows 667kOhm, 700 kOhm and 633 kOhm. I think these should all be without the “k”…would make a lot more sense.

Frederico Pontes
2 years ago

In example 11.7 8 Ed. : “The output resistance Ro can be determined by setting V, = 0, which results in // Vid = 0. The transistor will then be operating in the common-gate configuration with a resistance RF in the source lead.”

It seems wrong. The inverting input is connected to the feedback sensing resistor.
In order to determine the output resistance, place a test current source in series with the MOS drain terminal. The current of this source will flow across the RF resistor, producing a feedback voltage. Avaliating the voltage developped over the test current source, the value of Rof (Rof with feedback) is about 20 Mega Ohms. One can simulate this procedure using a circuit simulator, placing a voltage controlled voltage source with a gain of 0,002 (A/V) with a paralel 20K resistor insted the MOSFET. The same is valid for the opamp (VCVS).

Frederico Pontes
2 years ago

Sorry: 40 Mega. This is the result in the book, probably a coincidence.

Frederico Pontes
2 years ago

Reavaliating the book procedure, I found it correct. My procedure is a method to determine the same value, not using feedback theory, The final value is 38,6 Meg, not a simple coincidence. So, I agree with the procedure and the result.

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